Please disregard the earlier message under the PowerPoint.....
When we started the lab, the vinegar had a pH of 2. This puts it at the acid end of the pH scale. the scale goes from 1 (acid) to 14 (base). With the addition of an antacid the acidity of the vinegar was raised to 6, which is close to being neutral (7). The reason the vinegar is neutralized more or less is because in an acid there are H+ molecules and there are OH- molecules in the antacid, when these are mixed the H+ reacts with the OH- and the resulting product is H2O along with any other molecules that may have been present in the vinegar and antacid. the more water that is formed the more neutralized the solution becomes. If there is more of an acid than a base then the solution will be more acidic, less than 7 on the pH scale. The opposite is true for if there is more base, the solution will be more basic, more than 7 on pH scale. The approximate pH is found using limus paper which changes color according to pH. Another way to find pH is with numerical values using a log equation, much more precise but takes time because you have to find the values needed to calculate it.
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